mjd

27 ms·

1. 421.▲
   by mjd 9y ago

   I have no problem with that in general. The cereal-eating was focused and vivid (it was Cap'n Crunch), and anyway it was over in a couple of pages. Nicholson Baker's entire novel The Mezzanine is like that, and it's just
2. 422.▲
   by mjd 9y ago

   I said very much the same thing in my review: “[The characters] spend most of the third part literally doing nothing. They are assembled into a team of seven by a nebulous authority for some secret purpose; neither they nor we are told wh
3. 423.▲
   by mjd 9y ago

   By the way, I was on the big island of Hawai‘i last month and I drove past Pszyk Road. As well as I can discover, this was named for a Polish immigrant whose descendants now have names like Harmony Wai‘olohe Pszyk.
4. 424.▲
   by mjd 9y ago

   Thank you sir! I thought of you while I was writing it, and hoped that I would not make you feel embarrassed on my behalf.
5. 425.▲
   by mjd 9y ago

   Right, thanks!
6. 426.▲
   by mjd 9y ago

   Another Polish-speaker who read this article said she was delighted by my use of “ogoneks” instead of “ogoneki”.
7. 427.▲
   by mjd 9y ago

   Thank you both for your kind words!
8. 428.▲
   by mjd 9y ago

   tl;dr
9. 429.▲
   by mjd 9y ago

   In case you misted it, I mentioned your success with Levenshtein-per-unit-length in one of the followup articles. ( http://blog.plover.com/lang/anagram-scoring-3.html ) Thanks for looking into this so thoroughly.
10. 430.▲
    by mjd 9y ago

    This is a great idea, thanks! By my method, the top scorer is ACEEEFFGHHIILLMMNNOORRSSSTUV (25 points), which is the pseudonym of 17th-century German writer Hans Jakob Christoffel von Grimmelshausen. See if you can guess where he got his p
11. 431.▲
    by mjd 9y ago

    My current favorite is “Cheryl Burke” / “huckleberry”. (Cheryl Burke is one of the professional dancers on _Dancing with the Stars_.)
12. 432.▲
    by mjd 9y ago

    I enjoyed this a lot. Thanks for doing it. Code for scoring anagrams according to my method is at https://github.com/mjdominus/anagram-scoring if you would like to use that.
13. 433.▲
    by mjd 9y ago

    I would like that, and if someone built an EPUB I would host it on my site.
14. 434.▲
    by mjd 10y ago

    Just bad luck. It was scheduled maintenance and the site happened to be offline for 29 minutes.
15. 435.▲
    by mjd 10y ago

    THERE ARE NO WEASELS ON THE MOON
16. 436.▲
    by mjd 10y ago

    I agree with you, and I was worried about this point myself while I decided to include the example in the article. In Spanish “notaries” is certainly not an anagram of “señorita”. I eventually decided along the lines of cdelsolar’s comment
17. 437.▲
    by mjd 10y ago

    The Reddit discussion of this, though brief, was interesting and to the point. https://www.reddit.com/r/git/comments/5i3mpz/another_git_cat...
18. 438.▲
    by mjd 10y ago

    Thanks for the kind words!
19. 439.▲
    by mjd 10y ago

    I have worked for ZipRecruiter for 3½ years and I really like it. Very few people leave. Unlike a lot of profitable companies, we do something really valuable: we help people find jobs. If you want to ask me questions about it, you can em
20. 440.▲
    by mjd 10y ago

    My further thoughts on this, from 2006, are in this blog article, “Design Patterns of 1972” http://blog.plover.com/prog/design-patterns.html
21. 441.▲
    by mjd 10y ago

    I think it's a little simpler to observe that fo1 - fo2 = fe1 - fe2 The left side is an odd function and the right side is an even function, so the common value must be both odd and even. But only the zero function is both od
22. 442.▲
    by mjd 10y ago

    I checked with Frew on this, and we still don't know the answer.
23. 443.▲
    by mjd 10y ago

    That is a good point. I still don't know the answer to that! I _think_ it's that the sysadmins added the new capability to Perl sometime in the last few weeks, and the the problem then didn't appear until after the next tim
24. 444.▲
    by mjd 11y ago

    Any distribution suffices, as long as it is everywhere positive.
25. 445.▲
    by mjd 11y ago

    Rolling 1d20 doesn't work, because if the first player always chooses numbers bigger than 20 or smaller than 1, the second player wins with only probability ½. To get a winning probability greater than ½ the second player needs to choo
26. 446.▲
    by mjd 11y ago

    No. The first player can pick any numbers whatever, and the second player should pick a real number from a distribution that is everywhere positive, so the "range" is from minus infinity to plus infinity.
27. 447.▲
    by mjd 11y ago

    A more detailed (and formal) analysis is on math.se, here: http://math.stackexchange.com/questions/655972/help-rules-of... All the people saying that the strategy described doesn't work are mistaken; the para
28. 448.▲
    by mjd 11y ago

    You're right, but it doesn't have to be uniform, and of course it can't be. It only needs to be everywhere positive. I wrote it up in more detail here: http://math.stackexchange.com/questions/655972&#x2F
29. 449.▲
    by mjd 11y ago

    I believe the GNU regex library also uses a hybrid algorithm.
30. 450.▲
    by mjd 11y ago

    The linked page was first published 1 February 1998. The reduction from 3COL was added 12 June 1999.