4 ms·
I think it's a little simpler to observe that fo1 - fo2 = fe1 - fe2 The left side is an odd function and the right side is an even function, so the common
by mjd 10y ago
I think it's a little simpler to observe that
fo1 - fo2 = fe1 - fe2
The left side is an odd function and the right side is an even function, so the common value must be both odd and even. But only the zero function is both odd and even, QED.
- tamana 10y agoYour don't even need to posit fe3 and fo2: f(X) = e(X) + o(X) f(-X) = e(X) - o(X) From there you can explicitly solve the system of linear equations to get e(X) and o(X)