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Rolling 1d20 doesn't work, because if the first player always chooses numbers bigger than 20 or smaller than 1, the second player wins with only probability ½.
by mjd 11y ago
Rolling 1d20 doesn't work, because if the first player always chooses numbers bigger than 20 or smaller than 1, the second player wins with only probability ½.
To get a winning probability greater than ½ the second player needs to choose from a distribution that is everywhere positive, which means that a discrete distribution won't do.
- deleted 11y ago[deleted]
- fenomas 11y agoAh, I see what you mean - I meant that any old number will suffice for having a non-losing strategy, assuming that the opponent's strategy is unknown and undefined.