lengads

4 ms·

1.
by lengads 12y ago
Here, for example, is the implementation of `atom` (I think): /(atom /{ /\[\S\+\]/{ s/.*/[]/ bpop_context } s/.*/t/ bpop_context }
2.
by lengads 12y ago
I quite like the idea of calling one's workplace a ship. I'll take that expression on board, sea if it floats.
3.
by lengads 13y ago
"[TODO: Too tired to complete the docs. If you feel like contributing, please take a look at the routers and send a pull-request.]" I approve of this kind of API documentation.
4.
Good Tools(b-list.org)
1 points by lengads 13y ago|0 comments
5.
by lengads 13y ago
Is that to say that you.. wait, what are you doing?
6.
by lengads 13y ago
London, UK - CrowdScores http://crowdscores.co.uk - Full stack developer (Python, Javascript) We would love you to join our small team of passionate hackers to help use crowdsourcing and big-data to improve the collection of foo
7.
To learn why you should skim this post, please read it carefully(greghendershott.com)
5 points by lengads 13y ago|0 comments
8.
by lengads 13y ago
jrnkntl notes above that this update is not available for Mac or Linux.
9.
by lengads 13y ago
London, UK - FULLTIME INTERN (REMOTE OKAY) CrowdScores: https://crowdscores.co.uk/jobs/ Do you live and breathe the world of football? Know what makes a good story? Do you enjoy building engaging conversations that lea
10.
A Week with Mozilla's Rust(relistan.com)
180 points by lengads 13y ago|102 comments
11.
by lengads 14y ago
re.findall() returns all non-overlapping matches. We need to use a positive lookahead on the third part of the pattern to stop it from consuming the non-character: re.findall(r"[^a-zA-Z]([a-zA-Z]+)(?=[^a-zA-Z])", ..)