3 ms·
re.findall() returns all non-overlapping matches. We need to use a positive lookahead on the third part of the pattern to stop it from consuming the non-charact
by lengads 14y ago
re.findall() returns all non-overlapping matches. We need to use a positive lookahead on the third part of the pattern to stop it from consuming the non-character:
re.findall(r"[^a-zA-Z]([a-zA-Z]+)(?=[^a-zA-Z])", ..)