3 ms·

There isn't necessarily just one. A rectangle-ish form could have 4.

• amelius 2y ago
  Yes, rectangle would also be degenerate. Basically any configuration where adding an epsilon weight somewhere generates a non-epsilon shift so to speak.
  • eternauta3k 2y ago
    To me, "degenerate" means that it has a symmetry so that the different states are somehow identical (e.g. equal energy in a quantum system). If it's rectangle-ish (say, an imperfect hand-drawn rectangle) then it has 4 distinct equilibrium positions. Not sure if we're thinking of the same with "degenerate".
  • marcosdumay 2y ago
    You mean unstable?
  • s1artibartfast 2y ago
    A plus shape "+" has four stable equilibriums which all stable optimums, resistant to weight and self correcting.