vedant

7 ms·

31.
by vedant 14y ago
It's worth noting that aerial battle does occur in Tolkien's work. In the Silmarillion, Earendil the mariner sails on his flying ship to Middle-earth during the War of Wrath, and helps the Valar and eagles defeat Ancalagon, Morgoth's flying
32.
by vedant 14y ago
Yes. The radius of the "event horizon," which is the spherical boundary that serves as the point of no return, grows as it swallows more mass. For a Schwarzschild black hole (which doesn't rotate and has no charge), the event horizon radius
33.
Election prediction in Python a la 538(vedantmisra.com)
3 points by vedant 14y ago|0 comments
34.
by vedant 14y ago
The traction graph has a terrible y-axis. Equally spaced ticks measure 500, 1.5M - 500, 500k, 1M, and 600k. Many people who notice that will think it is meant to deceive, regardless of whether that was the intention.
35.
by vedant 15y ago
This is a question you can answer yourself by simply clicking on their github link. Their four public repositories are in C, Lisp, C++, and Java.
36.
by vedant 15y ago
Alas, the only winning move with "begging the question" is to not play. Insist on its proper use as a logical fallacy and you're a pedant; misuse it and draw the ire of grammarians and Aristotelians. Solution: "this raises the question."
37.
by vedant 15y ago
Douglas Adams is rolling over at this title. It should be "So Long, Google Maps..."
38.
by vedant 15y ago
Since Paul Erdos is one of the most prolific mathematicians ever, the problem is more likely that the default chain length (4) is too long for even a relatively large corpus. A chain length of 2 does much better.
39.
Markov chain paper title generator(vedantmisra.com)
36 points by vedant 15y ago|10 comments
40.
by vedant 15y ago
The academic index equation---probably the most crucial part of the article---could have been more clearly explained with, well, an equation (or two). Instead, it is a 626x752px image of words and arrows and nested fractions, and there's a
41.
Elevator algorithms(vedantmisra.com)
59 points by vedant 15y ago|12 comments
42.
by vedant 15y ago
Nobody had computed the percentage: Using 2e12 SMS messages/year, 160 characters/message, and 1 byte/character: (2e12 * 160) / (365 * (2^30)) = 816.501983 GiB/day So 10GiB/day is about 1.2% of daily SMS traffic. EDIT: Too slow.
43.
by vedant 15y ago
Machine learning is concerned with developing algorithms that enable programs to use data to evolve new behavior. Calling it a meme seems to put it in the same category as advice animals and Old Spice ads. Still, I see what you're saying-
44.
Quantifying the trendiness of trendy names(vedantmisra.com)
2 points by vedant 15y ago|0 comments