3 ms·
Yes. The radius of the "event horizon," which is the spherical boundary that serves as the point of no return, grows as it swallows more mass. For a Schwarzschi
by vedant 14y ago
Yes. The radius of the "event horizon," which is the spherical boundary that serves as the point of no return, grows as it swallows more mass. For a Schwarzschild black hole (which doesn't rotate and has no charge), the event horizon radius is 2GM/(c^2), where c is the speed of light, M is the mass of the black hole, and G is the gravitational constant.
The singularity at the center doesn't grow. But a black hole's "size" generally refers to the radius of its event horizon.
Wolfram Alpha computes it for you:
http://www.wolframalpha.com/input/?i=schwarzschild+radius+for+100+solar+masses http://www.wolframalpha.com/input/?i=schwarzschild+radius+fo...
- bcbrown 14y agoI learned this interesting factoid in an astrophysics class. All data is from Wolfram Alpha: Mass of universe: 3 * 10^52 kg Schwarzschild radius for that mass: 4.455 * 10^25 meters Volume of sphere with that radius: 3.704 * 10^77 m^3 Density = mass / volume = 8.099 * 10^-29 g/cm^3, or roughly 8 times the approximate universe density I think it's interesting that a universe-sized black hole would be a mass within an order of magnitude of the universe's mass.
- deleted 14y ago[deleted]
- CamperBob2 14y agoIsn't the ratio between dark matter and 'normal' matter something on the order of 8:1 as well?