tika

3 ms·

1. 1.▲
   by tika 11y ago

   271 is rather small. Which means this fake prime was quite easy to generate.
2. 2.▲
   by tika 11y ago

   :D
3. 3.▲
   by tika 11y ago

   Yes, but 1/2^80 is ridiculously large compared to 1/2^1024.
4. 4.▲
   by tika 11y ago

   "There are 2^1024 - 2^1023 = 9.0e307 1024-bit numbers" This is the count of 1023 bits numbers [(x - x/2) = x/2]. 0 is a valid leftmost digit.
5. 5.▲
   by tika 11y ago

   2^1024 is a lot larger than 2^80. The implication is clear.