colinbeveridge

7 ms·

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by colinbeveridge 1y ago
I understand that Professor Yaffle -- the woodpecker bookend in the classic kids' TV show Bagpuss -- was loosely based on Russell.
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by colinbeveridge 2y ago
After reading Tim Dellinger's article[^0] on performance, I wondered what distribution the firing system he alludes to would lead to. TL;DR: under some not-too-outlandish assumptions, it certainly quacks like a Pareto distribution. [^0
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A plausibly Pareto performance model(github.com)
2 points by colinbeveridge 2y ago|1 comments
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by colinbeveridge 2y ago
SEEKING WORK Location: Dorset, England (Remote) CV: https://colinbeveridge.co.uk/cv/CV_Colin_Beveridge_mathemati... Email: colin@colinbeveridge.co.uk I'm a mathematician who can code and write. I love solving prob
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by colinbeveridge 2y ago
Location: Dorset, England Remote: Yes, only Willing to relocate: No Technologies: Mainly go and python, but willing to learn. CV: https://colinbeveridge.co.uk/cv/CV_Colin_Beveridge_mathemati... Email: colin@colinbeveri
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by colinbeveridge 2y ago
Location: Dorset, UK Remote: Only Willing to relocate: No Technologies: Go, Python, versatile Résumé/CV: https://www.dropbox.com/scl/fi/7rz657fdb5bwtlap5kqhn/CV_Colin_Beveridge-2.pdf?rlkey=e53
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by colinbeveridge 2y ago
SEEKING WORK - Dorset, UK, remote - mathematician Hi! My name is Colin and I am a mathematician. I love solving problems and communicating the solutions. Looking for short- to medium-term contract/consulting work, but open to discussin
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by colinbeveridge 3y ago
For 13ths, multiply your base number by 77, subtract 1, and concatenate the number that makes it up to 999. So, for 4/13: * multiply 4 by 77 to get 308 * subtract 1 to get 307 * concatenate 692 to get 307692 4/13 is 0.[307692] rec
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by colinbeveridge 3y ago
A trick I learned -- I think from Colin Wright -- involves powers of 2. * Write the powers of 2 up to 2^10 in lex order and pop a decimal point after the first digit of each: * 1.28 * 1.6 * 2 * 2.56 * 3.2 * 4 * 5.12 * 6.4
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by colinbeveridge 4y ago
For example: > Oi oi, fallible developer! I, idiot programming enthusiast, frequent Hacker News, mixed subject extravaganza, do you? No way! This uses each Scrabble tile once (with blanks M and X).
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by colinbeveridge 4y ago
If you're interested in pangrams, you might like Dave's Scrabblegrams: https://twitter.com/dc_scrabblegram Use each tile from a standard Scrabble set once to make a meaningful sentence.
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by colinbeveridge 4y ago
Nice. I like ln(3) and ln(5) (1.1 and 1.6) as well.
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by colinbeveridge 4y ago
For the square root, I get 140.3. My heuristic is to find a nearby square (here, 140^2 = 19600) and divide the discrepancy (83) by double the root of the nearby square (280). This is the number to adjust by. [^0] [^0] The Maclaurin series e
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by colinbeveridge 4y ago
I did it similarly: log(19,683) is about 4.3, so ln(19,683) is about 4.3 * 2.3, which is about 9.9. That jumps out as close to 9ln(3). So the natural log of the cube root is (presumably) 3 ln(3), making the cube root itself 27. Alternativel
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by colinbeveridge 5y ago
Location: UK (South-west) Remote: only Willing to relocate: no Technologies: Mainly mathematics. Python, JS, some FORTRAN and SQL long ago. CV: https://flyingcoloursmaths.co.uk/cv/CV__Colin_Beveridge.pdf email: colin@f
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by colinbeveridge 11y ago
Here's a nice way to play with the parameters: https://www.desmos.com/calculator/3wrid37iir
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by colinbeveridge 13y ago
There's a nice demonstration of a zero-knowledge protocol here: http://aperiodical.com/2012/03/using-a-zero-knowledge-protoc...
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A remarkable mathematical morning(aperiodical.com)
1 points by colinbeveridge 14y ago|0 comments