4 ms·
Let's work out how that would work, in a simplified model of the world. Let's say you have a 1000mAh battery at 10V that weighs 100g (these numbers have all be
by lambda 11y ago
Let's work out how that would work, in a simplified model of the world.
Let's say you have a 1000mAh battery at 10V that weighs 100g (these numbers have all been made round for purposes of easier arithmetic). Everything else on your drone is weightless, and your motors have perfect efficiency. To keep this aloft, you need to overcome 9.8 m/s^2 that is applied by Earth's gravity; but since we're simplifying things, let's just round that to 10 m/s^2. 10 m/s^2 * 100g is 1 N, which means it requires 1 W of power to keep that battery aloft (resist the force of gravity). 1Ah * 10 V = 10 Wh, so that means you could stay aloft for 10 h (remember, these numbers are unrealistic, we have ignored any kind of efficiency, or the weight of the rest of the drone, etc).
So, lets use two batteries. Now we have 20 Wh of energy available, but we're holding up 200g of battery, which requires 2 W of power to stay aloft, so again, we can stay aloft for just 10 h.
And remember, all of this was ignoring any notion of efficiency or the weight of any other part of the craft to support this. As you increase the weight, motors will need to get more powerful to be able to actually keep it aloft, which means they need to get bigger, which is extra weight that you need to support that isn't giving you any extra energy. So the real world is actually even worse than our idealized model; as you add on more battery, only a fraction of the increase in weight adds more energy, so you will actually see shorter flight times.
Now, of course, there are designs for which increasing the amount of battery can lead to increased flight times. If the power supplied by the motors is sufficient to sustain the extra weight, so they don't need to be scaled up, then increasing the amount of battery relative to the rest of the weight of the craft can lead to higher efficiency as there is less relative "dead weight" (weight besides the batteries, that is not carrying energy). But that can only take you so far, which is why the flight times of drones plateau at a certain point and you can't fix it by just adding more battery.
This is why you don't see electric helicopters carrying people. The energy to weight ratio for batteries is too low; only fossil fuels have a sufficient energy density.
- gus_massa 11y agoI agree with your general idea, more than half an hour is not posible with the current technology. But I think this conversion is wrong: > let's just round that to 10 m/s^2. 10 m/s^2 100g is 1 N, which means it requires 1 W of power to keep that battery aloft* To transform some force into power, you need to multiply it by a speed (m/s). My favorite example is that a brick resting on a table can "hover" without spending any power (for a weird definition of "hovering"). I think the correct calculation involves the density of the air, to estimate the speed of the air that must be pushed down.
- lambda 11y agoEr, yeah, of course you're right. Adding that factor in will mean adding in even more fake, hand-wavy numbers, but doesn't really change the end result; whatever value you end up with, if you double the weight of the batteries, you will need to displace twice as much air (or move it twice as fast) to compensate, which means you'll need to use up twice as much energy, leaving you with the same flight time in the end.