4 ms·
If you implement one of the bounty algorithms you get the bounty, but you also get a payment when your algorithm is used. It's not going to make you a millionai
by web007 12y ago
If you implement one of the bounty algorithms you get the bounty, but you also get a payment when your algorithm is used. It's not going to make you a millionaire, but if you work in $FIELD_OF_STUDY and want to make a couple bucks in your spare time it might be worth it.
It's also likely that someone who wants to enter $FIELD_OF_STUDY might use one of these as a portfolio piece. You learn-and-implement one of these algorithms to get an introduction to the field, you get a bullet point for your resume and you make a few bucks.
- j2kun 12y agoYou get 1 credit/sec of your algorithm being used, and you need a million credits to get $100. If someone is continuously running your algorithm all day every day then you'd make about $300/month. That's fine for students and hobbyists, but not for someone who spends years devising a single algorithm worthy of widespread use, and in those cases the usual software libraries (numpy, R, etc) will implement them for free.
- doppenhe 12y agoThats just the cost of compute time, you the developer get to choose the cost in credits per call. https://algorithmia.com/pricing https://algorithmia.com/pricing
- chris_va 12y agohttps://algorithmia.com/docs/marketplace#pricing https://algorithmia.com/docs/marketplace#pricing "Royalty Algorithm developers may choose to set a cost-per-call royalty associated with their algorithm"
- sitkack 12y agoWhat incentive is there to make it run fast? The market tendency will attract useful but slow algorithms, second order effect would be to make it fast, undercutting the original authors rev stream. This is a fantastic race to the bottom. Too bad the dollar incentives are too low for this to actually work. You have no buyers, and the sea of open source software is your competition. The fully baked stuff, Matlab, Mathematica exists for a reason, it isn't just the algorithms.