4 ms·

Since he's talking about undefined behavior in a lot of the cases, the answer to all your questions is, "Yes." That's pretty obvious, so maybe he thought it wen

• fizixer 12y ago
  Not sure which of my questions you're referring to. As I replied to others, saying "bar() is invoked" is not only not obvious, it's incorrect. bar() may or may not be invoked.
  • heinrich5991 12y ago
    That's correct, what he wanted to say is probably that there exists compilers where `bar()` is invoked. Don't be so snarky, try to understand what the author ment.
    • Gibbon1 12y ago
      It's up to the author to show us this mythical compiler.
      • Dylan16807 12y ago
        It's up to the author to show that it's a valid compiler, no more. The question is whether a behavior is valid, not whether it is mandatory. Odd of you to use 'mythical' when one of the most common compilers in existence does this.
  • valleyer 12y ago
    You are misparsing. He's effectively saying: imagine you are testing this code, and x == NULL but "bar() is invoked". Is the compiler buggy?