5 ms·
Just zip(seq, seq[1:]) Won't work with iterator though.
by Suor 12y ago
Just
zip(seq, seq[1:])
Won't work with iterator though.
- andreasvc 12y agoitertools.islice would work.
- Suor 12y agoNo it won't, unless you `tee` an iterator first.
- e12e 12y agoFYI, the official documentation of itertools has its very own pairwise example: def pairwise(iterable): "s -> (s0,s1), (s1,s2), (s2, s3), ..." a, b = tee(iterable) next(b, None) return izip(a, b) https://docs.python.org/2/library/itertools.html#itertools.izip https://docs.python.org/2/library/itertools.html#itertools.i...
- baq 12y agofor the record: the official itertools docs have a lot more examples than this one and they're all really worth knowing about if not studying.
- e12e 12y agoIndeed: all(a < b for a,b in zip(seq,seq[1:])) (Although one might want <= if checking to see if the sequence is sorted, rather than strictly ascending (that is, it can contain matching/repeated elements)).