5 ms·
How would there be many requests? Wouldn't it load the cache line once into the shared state and then spin waiting for the line to be invalidated before reloadi
by arielweisberg 12y ago
How would there be many requests? Wouldn't it load the cache line once into the shared state and then spin waiting for the line to be invalidated before reloading?
- a-priori 12y agoHonestly, I don't know how this interacts with cache lines. As far as I know, Intel has not released any official details about what the PAUSE instruction does other than that it slows down spin loops to a reasonable rate. The best source I know of for this information is the Intel® 64 and IA-32 Architectures Optimization Reference Manual (http://www.intel.com/content/dam/www/public/us/en/documents/manuals/64-ia-32-architectures-optimization-manual.pdf http://www.intel.com/content/dam/www/public/us/en/documents/...). It is fairly vague about what the instruction does, but gives some useful information in 13.5.3 "Spin-Wait Loops", as well as 8.4 "Thread Synchronization", and in particular 8.4.2 "Synchronization for Short Periods" which says: "On a modern microprocessor with a superscalar speculative execution engine, [a spin loop] results in the issue of multiple simultaneous read requests from the spinning thread. These requests usually execute out-of-order with each read request being allocated a buffer resource. On detection of a write by a worker thread to a load that is in progress, the processor must guarantee no violations of memory order occur. The necessity of maintaining the order of outstanding memory operations inevitably costs the processor a severe penalty that impacts all threads." So it seems that the concern here is that (without a PAUSE) the speculative execution engine effectively unrolls the spin loop and executes a sequence of reads on the sequence variable. This queues up a list of pending memory operations that need to be unrolled in order to ensure that the result is the same as if they were executed sequentially -- even though in this case it wouldn't make any difference.
- arielweisberg 12y agoI think the harm here is for other threads on the same core that share the same queue of in-flight loads. Coherence wise it won't interfere with other cores and their access to memory. That said how hyper-threads share CPU resources is a moving target. My understanding through hearsay is that in the past many resources were statically partitioned with hyper-threading enabled, but now things are moving towards allocating resources dynamically which means that a thread wasting resources would be sucking up capacity that could be used by another hyper-thread.