No, they don't. x86 is a superscalar processor, and it does what all superscalar processors do--translate the instructions into µops for execution and dispatch

No, they don't. x86 is a superscalar processor, and it does what all superscalar processors do--translate the instructions into µops for execution and dispatch to the various execution units, with the µops not being 1-1 with the original instructions. However, it was supposed to be impossible for a CISC architecture to be superscalar, so this is what spawns the myth that it's somehow cheating by executing a RISC architecture under the hood.