4 ms·
It does? There is a fast drop followed by a long decay, exponential in fact. The cooling rate is proportional to the temperature difference, so the drop is shar
by coder68 7mo ago
It does? There is a fast drop followed by a long decay, exponential in fact. The cooling rate is proportional to the temperature difference, so the drop is sharpest at the very beginning when the object is hottest.
- amelius 7mo agoI mean that initial drop doesn't look like it is part of the same exponential decay.