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I am quite confused looking at that final; it seems incredibly basic for even an introductory course at MIT (that might have been a midterm when I was the gradu
by stephencanon 14y ago
I am quite confused looking at that final; it seems incredibly basic for even an introductory course at MIT (that might have been a midterm when I was the graduate instructor for linear algebra at Berkeley).
- deleted 14y ago[deleted]
- jaredlwong 14y ago18.06 is the very basic, more applied version of linear algebra at MIT. About half of the students that take it aren't in the math department. The more theoretical option is 18.700. And then there's 18.701, Algebra 1, taught by Artin using his book. The latter two are almost completely theoretical/proof based.
- stephencanon 14y agoTo be clear: I mean that it seems too basic even for a final exam of an introductory applied linear algebra course for non-majors.
- nessus42 14y agoYes, that is strange. It looks more like the mid-term of the linear algebra class that I took at MIT: i.e., 18.700. And I have to say that 18.700 was one of the easiest classes that I ever took at MIT. It's kind of a bummer that they gave me a C, in it though. I found it so easy that I never bothered to do the homework and just showed up for the exams and got A's on them all. For non-lab classes at MIT, they'd usually give you an A -- or at least a B -- if you got an A on all of the exams, even if you neglected the homework.