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Not the OP, but note that adding a std::string to a POD type makes it non-POD. If you were doing something like using malloc() to make the struct (not recommend
by nneonneo 10mo ago
Not the OP, but note that adding a std::string to a POD type makes it non-POD. If you were doing something like using malloc() to make the struct (not recommended in C++!), then suddenly your std::string is uninitialized, and touching that object will be instant UB. Uninitialized primitives are benign unless read, but uninitialized objects are extremely dangerous.
- IshKebab 10mo agoThat's not what was happening in this example though. It would be UB even if it was a POD.