3 ms·

It's not, it's the `socket2` library. The standard sockets don't allow (ab)using actual `UdpSocket`s as a different kind of datagram socket.

• IshKebab 11mo ago
  We're talking about UdpSocket: https://doc.rust-lang.org/stable/std/net/struct.UdpSocket.html https://doc.rust-lang.org/stable/std/net/struct.UdpSocket.ht...
  • Sharlin 11mo ago
    Yes, I know, but the point is that the standard UdpSocket is correctly named as it doesn’t represent any other datagram socket. Uh, we’re pribably in agreement here actually.
    • IshKebab 11mo ago
      Yeah exactly! :-D
• knorker 11mo ago
  Sure it does. let f = std::fs::File::open("/dev/null").unwrap(); let f: std::os::fd::OwnedFd = f.into(); let socket: std::net::UdpSocket = f.into(); This is really no different. In this example it's not even a socket.