4 ms·
The new non-commercial license is a bit of a doozy: https://huggingface.co/black-forest-labs/FLUX.1-Kontext-dev/blob/main/LICENSE.md https://huggingface.co/blac
by minimaxir 1y ago
The new non-commercial license is a bit of a doozy: https://huggingface.co/black-forest-labs/FLUX.1-Kontext-dev/blob/main/LICENSE.md https://huggingface.co/black-forest-labs/FLUX.1-Kontext-dev/...
- samtheprogram 1y agoIf I’m understanding this correctly, you can’t run this in a commercial setting, even if you’re not creating a derivative but simply generating outputs?
- smerrill25 1y agoI believe you can buy licensing? But def not the same as 'Open Weights..'
- StevenWaterman 1y ago"Weights available" perhaps
- stefan_ 1y agoThe same people that claim using all of humanities creation is fair use want you to pay for a bunch of MatMul inputs that are unrecognizable to anyone after quantizing them yourself.
- cchance 1y agoStupid question, whats to stop someone from quantizing it, shit even just barely finetuning it for 1 step and calling it something different, no ones actually checking WTF these models are based on when they're released, especially for the source models, especially if the release is not around the same time of release as the base, i'm 99% sure someone could fine tune SD3.5 a bit and release it today as Frizz 1.0 and people would just take it as a new model using the same layer structure as SD3.5 lol
- SV_BubbleTime 1y agoI forget which, but some HiDream maybe was called out for this when it happened to generate basically the same dude in front of the same archway when compared against flux.
- liuliu 1y agoHiDream is a separate architecture. OTOH, it might be finetuned on FLUX generated data, we will never know.
- doctorpangloss 1y agoHiDream is trained on AI generated outputs.
- SV_BubbleTime 1y agoYea, flux ones.
- elpocko 1y agoNot impossible but you'd gonna have to do a bit more than that. Most people are ignorant, but not all of them. An experienced user can tell what model family was used from a bunch of generated images. Also, no one would believe a nobody who just showed up claiming to have trained a brand new diffusion model.
- liuliu 1y agoThere is a simple method to detect this: taking a model "claimed" to be trained scratch, taking the model you suspected is the original, generate a new model = claimed_model * 0.5 + suspected_model * 0.5. If the claimed_model is trained from scratch, the new model will have 0 capability (basically generate gibberish words or noise). If it is a derivative of the suspected model, it will do something sensible. It is a bit more interesting for diffusion model because you can fine-tune to a different objective, making this investigation harder to do, but not impossible.
- doctorpangloss 1y ago
- whywhywhywhy 1y agoThe double standard is frankly disgusting. I'm actually all for open training but I think it's only fair you treat the model as your treated the life's work of others.
- ronsor 1y agoQuite frankly, I still believe that these model licenses are dubiously enforceable at best, and I'm skeptical that models are copyrightable at all.
- Hizonner 1y agoLicense for what? They don't have a copyright except maybe in the easily reimplemented Python code. Model weights are not copyrightable creative works, no matter how much various companies wish they were. At least they're not copyrightable until either legislatures extend the list of what's copyrightable, or courts have definitively show their willingness to reinterpret the words in the existing definitions far outside of their established legal meanings, their established meanings in common speech, and/or any sane analogy to those established meanings. Yes, I am aware that collections and databases are copyrightable. Models don't have the elements required for a copyrightable collection or database. I'm also aware that software is copyrightable. Models don't have the elements required for copyrightable software. They just flat out aren't works of authorship in any way. How much effort goes into creating them is irrelevant; that's not part of what defines a copyrightable work.