7 ms·
Step 1: Guess 00000. Step 2: Replace all grey cells with 1s.
by patrakov 1y ago
Step 1: Guess 00000.
Step 2: Replace all grey cells with 1s.
- petra303 1y agoYea, you don’t need more than two chances.
- arjvik 1y agoCame here to present my strategy for solving it in two tries, and realized it was far more complicated! (started with 00011)
- jesse__ 1y agoI think it's actually possible to win on the second guess with any initial input. Or at least I did it a handful of times..
- vikingerik 1y agoThis should be correct. For any cell that isn't green after your first guess, there's only one other possibility for its value.
- selcuka 1y agoYes. Yellow and grey mean exactly the same thing in this game: Flip it.
- IAmBroom 1y agoHoping that you are being sarcastic...
- dskloet 1y agoIt's not guaranteed you will always win in 2 steps because occasionally you will win in 1 step.
- Supermancho 1y agoIsn't 1 within the bounds of 2?
- Sohcahtoa82 1y agoThere's a difference between "in 2 steps" and "within 2 steps".
- Supermancho 1y agoSplitting hairs seems like grammar policing. I can even see action 1 and null action if I squint hard enough.
- paxys 1y agoStep 1: Guess anything Step 2: Flip all the non green cells.
- underlines 1y agoafaik, guessing anything not 00000 or 11111 at first step will lead to an optimum strategy of 3 steps. because you introduce possible "right digit at wrong place" as a third state. guessing 00000 or 11111 removes that third state and leaves you with simple substitution of wrong cells, which leads to an optimal 2 step strategy. but obviously the shortest strategy is just guessing it right on the first try :D lol
- heckelson 1y agoAnd for a second, I was proud that I solved mine in 3 steps...
- deleted 1y ago[deleted]
- 0xAFFFF 1y agoThis is obviously improper. The valid strategy for this game unfolds as follows. Step 1: Guess 11111. Step 2: Replace all grey cells with 0s. Thank you for your careful consideration.
- nmeofthestate 1y agoIf you start with 0's you save a small amount of electricity. 1's use up more electricity - any electronic engineer will agree.
- justsid 1y agoNot to ruin a joke, but does it actually make a difference for SRAM? It’s two inverters in a loop, despite not being the same size they are active components. But I’m also a software guy so I could be totally wrong.
- dskloet 1y agoI think displaying black or white pixels makes a bigger difference.
- bdcs 1y ago> does it actually make a difference for SRAM? I have no idea in practice. But for the thermodynamic limit of actually making a difference, any irreversible change requires heat to be generated, e.g. initializing to zero, truncating, or bitshifts with discarded information. In contrast, addition/subtraction/multiplication/bitshifts without over-/under- flow will not necessarily generate heat. https://en.wikipedia.org/wiki/Landauer%27s_principle https://en.wikipedia.org/wiki/Landauer%27s_principle PS. you can also use mass-energy equivalence to extend this to calculate the lower limit of mass for a given quantity of information. TL;DR: The internet weighs 50g https://www.youtube.com/watch?v=WaUzu-iksi8 https://www.youtube.com/watch?v=WaUzu-iksi8
- stavros 1y agoI got zero right: https://imgz.org/i6yJQnf4.png https://imgz.org/i6yJQnf4.png
- gus_massa 1y agoI solved it in one attempt! https://imgur.com/a/jklkc7F https://imgur.com/a/jklkc7F Spoiler alert: There is a nice video by Captain Disillusion https://www.youtube.com/watch?v=ou7KSmfC3lA https://www.youtube.com/watch?v=ou7KSmfC3lA (the relevant part is https://www.youtube.com/watch?v=ou7KSmfC3lA&t=275s https://www.youtube.com/watch?v=ou7KSmfC3lA&t=275s )
- Sesse__ 1y agoI intended this strategy, but 00000 happened to be correct, so I didn't even need a step 2.
- a3w 1y agoI think I saw a two. There is no such thing as a two, Bender!
- layer8 1y agoThere may be FileNotFound, though. https://thedailywtf.com/articles/what_is_truth_0x3f_ https://thedailywtf.com/articles/what_is_truth_0x3f_
- freedomben 1y agoThere should be a 1 in 1,000 chance that a two slips in to one of the puzzles, and then can't be reproduced.