3 ms·
Sorry, if there are N clients, and M servers, then there are N+M endpoints, but N*M links, which is a lot more.
by FabHK 2y ago
Sorry, if there are N clients, and M servers, then there are N+M endpoints, but N*M links, which is a lot more.
- Ey7NFZ3P0nzAe 2y agoWell all endpoints might differ but the links might rely on the exact same algorithm so you need to count distinct links
- PhilipRoman 2y agoThe link is only as strong as it's weakest... link? Anyway, given the structure of internet, I wouldn't say it is O(N*M), more like O(the number of major ISPs).