3 ms·
You mean 3,200+ m/s of delta-V.
by vkou 2y ago
You mean 3,200+ m/s of delta-V.
- JumpCrisscross 2y agoI actually made a comedy of errors when I went back and edited my first estimate ("about 300 m/s"). For debris to become a problem to us ground people, it really just needs to make it to LEO–the atmosphere will take care of it from there. So I was trying to estimate the Δv for L2 to LEO, which is about 200 m/s according to Table 3 on that source. So probably not 3 km/s. But 320 is too precise given the handwavy math I am doing.
- Dylan16807 2y agoThat's the delta-V to get away from Earth, and 90% of it is spent shifting from a circular low orbit into a transfer/escape orbit. When you're coming back, you don't need to spend that energy. Instead you slightly adjust your aim so your transfer orbit hits the atmosphere instead of missing it.