5 ms·

We can empirically prove that gravitation cancels out in the gravitational center of an object, if we will dig into Moon.

• mr_mitm 2y ago
  What does this have to do with singularities? No one expects any kind of singularity anywhere around or in the moon.
  • oneshtein 2y ago
    Singularity is not possible at 0G, isn't?
    • JumpCrisscross 2y ago
      > Singularity is not possible at 0G, isn't? One divided by zero is a singularity. Singularity, mathematically speaking, means your math breaks. Calculus gets around this problem with limits. But there is absolutely nothing about physics that prohibits singularities, even gravitational singularities, in a zero G space because by definition a gravitational singularity per se has an undefined G.
      • oneshtein 2y ago
        Singularity means that at least some barions will be at the same place in the same time, which against nature of fermions. Moreover, it hard to imagine that Higgs bosons will act at same place and time with same effectiveness. So, I cannot believe in a singularity unless it will be physically demonstrated.
        • mr_mitm 2y ago
          Sounds like you mean fermions. Bosons absolutely can occupy the same quantum states, look up the Bose-Einstein condensate. Also, no one serious claims that singularities exist when taking quantum mechanics into account. It's completely unknown territory.
          • oneshtein 2y ago
            I wrote «barions», but yes, you are right, I meant «fermions». Fixed.
          • JumpCrisscross 2y ago
            They’re mixing up barycentres [1] and baryons [2]. [1] https://en.m.wikipedia.org/wiki/Barycenter_(astronomy) https://en.m.wikipedia.org/wiki/Barycenter_(astronomy) [2] https://en.m.wikipedia.org/wiki/Baryon https://en.m.wikipedia.org/wiki/Baryon
            • oneshtein 2y ago
              Anyway, I propose to dig tunnel to the center of the Moon with plasma cutters and make a lab there. IMHO, the result will be worthy. As non-native speaker, it's hard for me to argue with native speakers (especially when I sick, tired, in army, and at war), and I refuse to use AI to translate, because I suspect that such messages will be automatically rejected by future archivists.
              • nathan_compton 2y ago
                Why not dig a tunnel to the center of a smaller body like an asteroid? I think you're talking about the fact that the gravitational force inside of a symmetric shell of matter is zero. But the potential is not, as can be (and has been, I believe) demonstrated quite easily by just putting a clock in a hole and measuring the time dilation relative to the surface. Sorry you are at war. Good luck.
                • oneshtein 2y ago
                  AFAIK, asteroids are nor solid, nor round. Moreover, their gravitational field is very low already. They are much further than Moon, so it will be harder to communicate. Moreover, the tunnel itself will create much stronger impact on results on asteroid, than on Moon. If we will dig ∅1 cm tunnel to the center of the Moon, it missing volume will be pretty insignificant and easy to compensate, e.g. with lead plug. Moreover, big and rigid Moon will be much better antenna for lot of experiments, than small and soft asteroid.
        • JumpCrisscross 2y ago
          > Singularity means that at least some barions will be at the same place in the same time The singularity in a black hole has no conception of baryons, hadrons or fermions. Those are quantum particles. The singularity is in general relativity. Also, 0G doesn’t mean zero gravity. An object in freefall is still subject to gravity despite experiencing 0G. (Side note: fermions can occupy the same place at the same time. They cannot occupy the same state. This seeming mathematic fuckery goes on to describe many real-world weirdos like neutron stars.)
        • deleted 2y ago
          [deleted]
      • api 2y ago
        If matter falling into a singularity never reaches it because time slows down infinitely as you approach, wouldn’t this be a physical representation of a mathematical limit from calculus? The actual literal 1d singularity never forms but it is approached infinitely close.
        • cyberax 2y ago
          Matter falling into a singularity reaches it in a fairly short time, according to the falling observer's clock. It's just that the _light_ that this observer emits takes infinitely long to reach observers outside of the singularity.