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Okay but how does this help the reader? If the worse code happens to optimize to the same thing it's still awful and you get no benefits. It's likely not to opt

Okay but how does this help the reader? If the worse code happens to optimize to the same thing it's still awful and you get no benefits. It's likely not to optimize down unless you have fast-math enabled because the extra float ops have to be preserved to be IEEE754 compliant

burnished 2y ago
..how is it awful if it has the same result?
- dcrazy 2y ago
  Because it perpetuates a misconception and is harder to read.
- seba_dos1 2y ago
  Just look at it.
account42 2y ago
Fragment and vertex shaders generally don't target strict IEEE754 compliance by default. Transforming a * (b ? 1.0 : 0.0) into b ? a : 0.0 is absolutely something you can expect a shader compiler to do - that only requires assuming a is not NaN.