3 ms·
> Therefore, s(x)=p∗(x)−x2n+2 We can now write, s(x)=p∗(x)−x2n+2 Completely repeated itself... weird... it also says "...more lines cut off..." How many line
by adverbly 2y ago
> Therefore,
s(x)=p∗(x)−x2n+2
We can now write,
s(x)=p∗(x)−x2n+2
Completely repeated itself... weird... it also says "...more lines cut off..." How many lines I wonder? Would people get charged for these cut off lines? Would have been nice to see how much answer had cost...