3 ms·

store it in the bytes before the start of the array. Maybe use a bit flag to indicate additional bytes if length is too much to store in one byte. Like unicode

• Someone 2y ago
  Do you know that, for statically defined arrays, you can get the size like this: int foo[10]; int ten = sizeof(foo)/sizeof(foo[0]); Of course, that doesn’t work if you do that with a function argument because you can’t pass arrays as arguments, only pointers, so a function can’t know whether a passed value is a statically defined array or dynamically allocated. int f(int * foo) { return sizeof(foo)/sizeof(foo[0]); // } int notTen = f(foo); That even is the case when you do things like these (https://stackoverflow.com/a/2375038 https://stackoverflow.com/a/2375038): int f(int foo[10]) { return sizeof(foo)/sizeof(foo[0]); } int notTen = f(foo); or int f(int foo[static 10]) { return sizeof(foo)/sizeof(foo[0]); } int notTen = f(foo);
• eimrine 2y ago
  > store it in the bytes before the start of the array Ah, Pascal strings. There is a reason why they have lost the battle.