3 ms·
It might predate HN but you are looking at the XY problem, not the YX problem. In this case, they are not commutative.
by rezonant 3y ago
It might predate HN but you are looking at the XY problem, not the YX problem. In this case, they are not commutative.
- dotancohen 3y agoIt seems that the YX problem is a derivative of the XY problem. In both cases we solve for X.
- Dylan16807 3y ago> seems If you're actually unsure, then be sure. It's a derivative.
- dotancohen 3y agoIt's a play on words.
- Dylan16807 3y agoCan you explain it? I don't get it. I mean, I see how "derivative" could be wordplay, but I don't see how "seems" is wordplay.
- brudgers 3y agoYes the YX problem has a YX problem.