3 ms·
Can you explain what you dislike about it? It's a different operator, certainly. I'm pretty sure that it has an "odd" shape, because indexing a list in Haskell
by TheBoff 14y ago
Can you explain what you dislike about it? It's a different operator, certainly.
I'm pretty sure that it has an "odd" shape, because indexing a list in Haskell is potentially O(n). The operator itself is essentially a warning...