3 ms·
Suppose your hoop probabilities are 25% and that you have two hoops so that the probability of jumping through both is 25% * 25% = 6.25%. You can reduce the
by nequo 3y ago
Suppose your hoop probabilities are 25% and that you have two hoops so that the probability of jumping through both is
25% * 25% = 6.25%.
You can reduce the size of one of the hoops in half, changing the probability to
25% * 25%/2 = 3.125%
You can also add a third hoop, in which case the probability is
25% * 25% * 25% = 1.5625%
1.5625% < 3.125%, so adding a third hoop is better than shrinking one of the two existing hoops. Of course, this argument makes important assumptions about the hoop probabilities.
- 0xDEAFBEAD 3y agoMakes sense. Other key questions would be: complexity cost of added hoop (including, possibly, increased attack surface -- the sequence of hoops is just an abstraction that reality may not obey) and also creation difficulty (it could be that improving an existing hoop is significantly quicker than creating a new one).
- krab 3y agoThe probabilities aren't independent. The person jumping through the first hoop is probably more able than average. Therefore, any additional hoop - if it doesn't require a completely orthogonal skill - is less selective.
- 0xDEAFBEAD 3y agoI think it depends on what the "probability" is meant to indicate. You're correct if it's meant to indicate whether a particular attacker can get through a particular hoop. But probabilities could also refer to e.g. the chance that it's possible to get through a particular hoop, period. Or the fraction of some input space which corresponds to an exploitation.