4 ms·

Being closed really isn't an obstacle. For example you can solve a euclidean modulus toroid by just tiling the space once more around itself, running a vanilla

• amelius 3y ago
  If the pointset is degenerate (e.g. 4 points on a circle), then you may get different local results in different copies of the space and the unioning may be difficult.
  • Rhapso 3y ago
    Ah, I'm an engineer not a theorist. Such degenerate input is unlikely to be a valid use case, can be detected, and I can reject it. Wait until you see the actual heuristic I use for solving voronoi/delaunay in arbitrary topologies. I need to write a blog post on it anyways.
    • amelius 3y ago
      It's very easy to get 4 points on a circle. In 2d space just the four corners of a unit square would do it.
      • Rhapso 3y ago
        On a sphere or modulus space, that just becomes a K4, so it isn't even an edge case, it is the solution that the approximation would generate.
        • amelius 3y ago
          Yes, you definitely have to deal with it, in virtually any setup.