3 ms·
It’s backwards. For A to be assignable to B, A must implement B, so A’s methods must be a superset of B’s.
by fanf2 3y ago
It’s backwards. For A to be assignable to B, A must implement B, so A’s methods must be a superset of B’s.
- the_gipsy 3y agoAh, now I get it - sorry for adding to the confusion!