3 ms·

Just like FPP is incompatible with C, I agree. And if you want a real taste of FPP go with either Haskell, OCaml or even the good ol' LISP

• adamnemecek 3y ago
  Or Rust.
  • kadoban 3y ago
    My contention that FP has no meaning gains another point of evidence.
  • stevefan1999 3y ago
    As a Rust guy, I disagree. For one, Rust does not have lazy evaluation, just like C which is why I raised the point C is incompatible with FPP. Lazy evaluation in C (and Rust) can be emulated by function pointers (and closures), but it is not easy to use
    • worrycue 3y ago
      > Rust does not have lazy evaluation Does one need lazy evaluation to be FP? Scheme isn't lazy to my knowledge.
      • spookie 3y ago
        I'm sure it would make a compiler's optimization job easier.