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> The article has a great flow chart in it that highlights rejected energy and energy services and where the rejected energy comes from. energy here spans the s

by zokier 3y ago

> The article has a great flow chart in it that highlights rejected energy and energy services and where the rejected energy comes from. energy here spans the spectrum of electricity generation, heating, industrial usage, transport, etc. > Basically more than two thirds of the energy is lost to heat, friction, noise, transmission losses, etc. Most of the losses are coal, gas, and oil. To uninitiated like me the chart was really confusing. In many sectors doesn't almost all energy get ultimately lost in some way? Like in computing all electricity just becomes waste heat, or in transportation unless you move goods up a mountain all the energy is just lost?

Trombone12 3y ago
> Like in computing all electricity just becomes waste heat I mean, not all of the IT sector is ad-tech you know; for example, many would argue that the systems durably recording how much money you own provide a useful service.
IggleSniggle 3y ago
"Lost" means spent towards nobody's useful purpose. Nobody used the output in any way. In transportation, you used your car to get from point A to point B. You don't care about the heat or noise or whatever that you generated. That energy was "lost." If somebody harvested that same energy directly from your vehicle for some purpose, like making fried eggs on your engine block, then the portion used to fry your egg would no longer be "lost"
- zokier 3y ago
  That just seems either an impossible, or just useless measurement. I guess for industries like aluminum smelting you can say the product captures significant part of the energy put into the process, but most human activities are not like that. For example machining/casting that raw aluminum stock into some intricate product, all the energy ends up as waste because from physics point of view that intricate object doesn't contain any more energy than the raw stock material. If that is how its considered, then I struggle to understand how the rejected energy is not closer to 100%
  - ianburrell 3y ago
    The important question is how much energy do they need to put in to get the result. The goal can be machined aluminum or car at destination. For lots of processes, the output energy, like moving car or shining light, is important and the goal. Higher efficiency means can put in less energy and get the same result. Light ends up as heat, but LEDs are more efficient cause they don’t produce extra heat. Electric motors are more efficient than combustion ones so electric cars end up going farther for same input.
    - zokier 3y ago
      Sure, it is reasoably easy to say that A is more efficient than B, and even quantify how much energy A saves in comparison to B. But that is only a relative measure; it is far less obvious how you'd quantify the waste in absolute terms like the chart in question here seems to do? To do so you'd need to know some theoretical ideal minimum energy process that would get some equivalent end result as a reference point, but that seems wildly infeasible to estimate
  - fnordpiglet 3y ago
    In your example of machining the useful energy consumed was in the kinetic energy transferred by the motor into the bit. The noise and heat and other forms of energy dissipation that didn’t go directly into machining the object were wasted or lost. If your goal is the machined part, any energy that wasn’t directly necessary or if it’s expenditure were zero and the part would have been machined identically, is considered a waste or lost energy. The “lost” doesn’t mean the rest of the energy were somehow captured or retained, but that it was captured productively towards some goal. Perhaps the term is confusing or misleading, but that’s what it’s intended meaning is.
    - p1mrx 3y ago
      > the useful energy consumed was in the kinetic energy transferred by the motor into the bit. This doesn't solve the problem, because the final machined part is not moving, and thus has no kinetic energy. In order to get an efficiency number, we would have to know what 100% means. Maybe it's possible to calculate the minimum energy required to break the chemical bonds spanning a given cross sectional area of solid aluminum? I imagine that you could (very theoretically) recover this energy by cold welding the aluminum back together a vacuum.
marcosdumay 3y ago
The text line under it tries to explain the concept, but fails due to brevity. I believe (by looking at the numbers there) it counts as "loses" everything that happens due to energy conversion, and "useful work" everything that happens with the final form of the energy. If that's the case, friction inside an internal combustion engine counts as loses, but at the wheels of a car counts as useful work.

by zokier 3y ago

Trombone12 3y ago

> Like in computing all electricity just becomes waste heat I mean, not all of the IT sector is ad-tech you know; for example, many would argue that the systems durably recording how much money you own provide a useful service.

IggleSniggle 3y ago

"Lost" means spent towards nobody's useful purpose. Nobody used the output in any way. In transportation, you used your car to get from point A to point B. You don't care about the heat or noise or whatever that you generated. That energy was "lost." If somebody harvested that same energy directly from your vehicle for some purpose, like making fried eggs on your engine block, then the portion used to fry your egg would no longer be "lost"

zokier 3y ago
That just seems either an impossible, or just useless measurement. I guess for industries like aluminum smelting you can say the product captures significant part of the energy put into the process, but most human activities are not like that. For example machining/casting that raw aluminum stock into some intricate product, all the energy ends up as waste because from physics point of view that intricate object doesn't contain any more energy than the raw stock material. If that is how its considered, then I struggle to understand how the rejected energy is not closer to 100%
- ianburrell 3y ago
  The important question is how much energy do they need to put in to get the result. The goal can be machined aluminum or car at destination. For lots of processes, the output energy, like moving car or shining light, is important and the goal. Higher efficiency means can put in less energy and get the same result. Light ends up as heat, but LEDs are more efficient cause they don’t produce extra heat. Electric motors are more efficient than combustion ones so electric cars end up going farther for same input.
  - zokier 3y ago
    Sure, it is reasoably easy to say that A is more efficient than B, and even quantify how much energy A saves in comparison to B. But that is only a relative measure; it is far less obvious how you'd quantify the waste in absolute terms like the chart in question here seems to do? To do so you'd need to know some theoretical ideal minimum energy process that would get some equivalent end result as a reference point, but that seems wildly infeasible to estimate
- fnordpiglet 3y ago
  In your example of machining the useful energy consumed was in the kinetic energy transferred by the motor into the bit. The noise and heat and other forms of energy dissipation that didn’t go directly into machining the object were wasted or lost. If your goal is the machined part, any energy that wasn’t directly necessary or if it’s expenditure were zero and the part would have been machined identically, is considered a waste or lost energy. The “lost” doesn’t mean the rest of the energy were somehow captured or retained, but that it was captured productively towards some goal. Perhaps the term is confusing or misleading, but that’s what it’s intended meaning is.
  - p1mrx 3y ago
    > the useful energy consumed was in the kinetic energy transferred by the motor into the bit. This doesn't solve the problem, because the final machined part is not moving, and thus has no kinetic energy. In order to get an efficiency number, we would have to know what 100% means. Maybe it's possible to calculate the minimum energy required to break the chemical bonds spanning a given cross sectional area of solid aluminum? I imagine that you could (very theoretically) recover this energy by cold welding the aluminum back together a vacuum.

marcosdumay 3y ago

The text line under it tries to explain the concept, but fails due to brevity. I believe (by looking at the numbers there) it counts as "loses" everything that happens due to energy conversion, and "useful work" everything that happens with the final form of the energy. If that's the case, friction inside an internal combustion engine counts as loses, but at the wheels of a car counts as useful work.