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That only proves that a compiler behaves according to a language definition. That does not prove the executables will behave as you expect the executables to be
by stingraycharles 15y ago
That only proves that a compiler behaves according to a language definition. That does not prove the executables will behave as you expect the executables to behave, and thus there is no way knowing the executables will be error free.
- Dylan16807 15y agoFrownie said error-free compilation, not error-free in all possible aspects.