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Pi may contain any sequence of digits but it's not proven that it contains all sequences of digits. IMHO, it's possible to construct a sequence of digits which
by oneshtein 3y ago
Pi may contain any sequence of digits but it's not proven that it contains all sequences of digits. IMHO, it's possible to construct a sequence of digits which will not be in Pi. It's easy to construct such sequence for first N digits of Pi of any length (for example, N zeroes).
- jakelazaroff 3y agoWe’re talking about a hypothetical scenario in which pi is normal, though.
- Dylan16807 3y agoConstructing things for N digit subsets can be misleadingly easy. It's easy to construct a sequence of digits that is larger than any N digit number. But it's obviously impossible for any such number to be the largest number.
- LodeOfCode 3y agoThis reasoning is true of every real number, yet it's been proven that almost all real numbers are absolutely normal and therefore contains every finite sequence of digits