3 ms·
Let α and β be the eigenvalues of the matrix A. A satisfies its characteristic polynomial so we have A^2 - (α + β)A + αβI = 0 If α /= β, define X = (A -
by edflsafoiewq 3y ago
Let α and β be the eigenvalues of the matrix A. A satisfies its characteristic polynomial so we have
A^2 - (α + β)A + αβI = 0
If α /= β, define
X = (A - βI)/(α - β)
Y = (A - αI)/(β - α)
which satisfy
X^2 = X
XY = YX = 0
Y^2 = Y
so for k >= 2, X^k = X and Y^k = Y. Hence
A^n = (αX + βY)^n
= α^n X^n + β^n Y^n
= α^n X + β^n Y
On the other hand, if α = β, define
Z = A - αI
which satisfies Z^2 = 0, so Z^k = 0, and
A^n = (αI + Z)^n
= α^n I + n α^(n-1) Z
- fweimer 3y agoThanks, that actually looks appropriately elementary.