3 ms·
Well the expected value of E[log2(rand())] is not the same as E[log(rand())] and therein lies the difference. See my sibling comment. Like I said, you can chec
by sobellian 3y ago
Well the expected value of E[log2(rand())] is not the same as E[log(rand())] and therein lies the difference. See my sibling comment.
Like I said, you can check this in a python terminal.