3 ms·
If other 'branches' are still detectable, then they're probably detectable by more than one means; say, gravitationally. Could this be an explanation of dark ma
by infogulch 4y ago
If other 'branches' are still detectable, then they're probably detectable by more than one means; say, gravitationally. Could this be an explanation of dark matter? That is, dark matter is the sum of tiny gravitational interactions between many mostly-split branches of the wave function.
- cwillu 4y agohttps://physics.stackexchange.com/questions/34993/reversing-gravitational-decoherence https://physics.stackexchange.com/questions/34993/reversing-... “What actually happens in an experiment with electrons is kind of interesting. Since photons are massless they are easy to excite if they have long wavelength and hence low energy. Whenever an electron gets accelerated many "soft" (i.e., long wavelength) photons get emitted. But if the acceleration is weak, the photons have such long wavelength that they provide little information concerning which path, and interference is possible. It is the same with gravitons. Except the probability of emitting a "hard" graviton (with short enough wavelength to distinguish the paths) is far, far smaller than for photons, and therefore gravitational decoherence is extremely weak.”