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> for instance .099... = .1000 wait, so how does diagonalization account for this? The argument, as i recall, was that every real number in the "fake list" dif
by chii 4y ago
> for instance .099... = .1000
wait, so how does diagonalization account for this? The argument, as i recall, was that every real number in the "fake list" differs from the generated real number by at least 1 position in the decimal expansion.
But doesn't this argument depend on the assumption that every real number has a unique decimal expansion?
- ouid 4y agoWell, the short answer is that there aren't that many related decimal expansions at most two for any expansion, and a countable number of pairs, but it's a problem with the argument.