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This looks like a really cool topic... but you need to know the basic definitions in order to understand the article or its parent. https://webusers.imj-prg.fr

This looks like a really cool topic... but you need to know the basic definitions in order to understand the article or its parent. https://webusers.imj-prg.fr/~pascal.michel/tmi.html https://webusers.imj-prg.fr/~pascal.michel/tmi.html Quoted so you don't have to dig for it: What is a busy beaver? Consider Turing machines with fixed numbers of states and symbols. If there are k states and n symbols, then the number of possible next move functions, or possible tables, is (2kn+1)^kn. Thus, there are (2kn+1)^kn Turing machines with k states and n symbols. Each of them can be launched on a blank tape, that is a tape with symbols 0 in all cells. Then some of them never stop, and the other ones eventually stop. Those which stop are called busy beavers. Busy beavers compete in two competitions: to take the most time to stop, to leave the most non-blank symbols on the tape when stopping.

vanderZwan 4y ago
It feels a bit similar to how Conway's Game of Life is a surprisingly deep rabbit hole with its own devoted niche community. I wonder how many of those types of math/programming niches exist.
- JadeNB 4y ago
  > It feels a bit similar to how Conway's Game of Life is a surprisingly deep rabbit hole with its own devoted niche community. I wonder how many of those types of math/programming niches exist. I'm not a programmer, though I suspect that that community is similar, except perhaps with fewer rabbit holes now just because it's younger—but research-level mathematics is essentially nothing but one after another rabbit hole with a devoted niche community. There's no topic so specialized that you can't find a mathematician for whom it's their everyday concrete research lab, and no mathematician so specialized that you can't find a topic even in their discipline on which they'll look down as meaninglessly abstract and application-free.
- ravi-delia 4y ago
  With BB it's not so surprising that it's weird because if it weren't, you could cheat! Say you know that a Turing machine which computers digits of the goldbach conjecture has n states. Then if you could just get BB(n), or even if BB(n) is too predictable, you could just run that Turing machine for over BB(n) steps and know it doesn't halt. So we can informally see that BB will necessarily be at least as hard as all of math. Nature abhors a vacuum, but math abhors a shortcut. Every time we find one, it turns out to be deeper and more beautiful than expected.
  - Hercuros 4y ago
    To be fair, even if you were able to get BB(n), it might still be (and probably is) some ridiculously large number, like a billion times the number of atoms in the universe or something. So that wouldn't really help you solve any math problems even if you were able to get the maximum amount of steps For a lot of things, like solving boolean SAT, we have the equivalent of a "busy-beaver" limit: if you want to solve a SAT instance of size n, you need at most 2^n steps. And being able to solve arbitrary SAT instances in reasonable time would be huge for mathematical proofs as well, because you could do stuff like find proofs up to a fixed size quickly. Point is that math is probably even harder than BB in some sense, since having BB would not really help you solve math problems in practice most likely.
    - ravi-delia 4y ago
      Oh absolutely, you could never actually use BB(n) even with an oracle on hand. I simplify to cheating on math mostly because it's sort of crazy to think about coming at a problem from that angle (if the Goldbach conjecture is false there's obviously some N where it stops holding, but it's bizarre that you can formulate an N which is independent of the question), but really BB is hard because it's such a slight relaxation of the halting problem. It is a little more interesting (to me at least) than SAT because you expect SAT to be as hard as math. I mean, it's basically just a proof done the long hard way. But even though BB(n) doesn't provide an especially useful upper bound, it does let you expand the halting problem out large enough to use as a bludgeon, since even having information about BB(n) would still let you cheat. It's fun that way!
  - dash2 4y ago
    Stupid question: does this imply that busy beaver machines might eventually tell us things about the rest of maths (like are there any real functions that you could say "ah the relevant machine runs for at least BB(n) steps and so we have proved X for infinity"?)
    - cwillu 4y ago
      Kinda, yes, although the implication is typically taken the opposite direction. There are busy beavers who's halting cannot be proven in ZFC! https://scottaaronson.blog/?p=2725 https://scottaaronson.blog/?p=2725

vanderZwan 4y ago

It feels a bit similar to how Conway's Game of Life is a surprisingly deep rabbit hole with its own devoted niche community. I wonder how many of those types of math/programming niches exist.

JadeNB 4y ago
> It feels a bit similar to how Conway's Game of Life is a surprisingly deep rabbit hole with its own devoted niche community. I wonder how many of those types of math/programming niches exist. I'm not a programmer, though I suspect that that community is similar, except perhaps with fewer rabbit holes now just because it's younger—but research-level mathematics is essentially nothing but one after another rabbit hole with a devoted niche community. There's no topic so specialized that you can't find a mathematician for whom it's their everyday concrete research lab, and no mathematician so specialized that you can't find a topic even in their discipline on which they'll look down as meaninglessly abstract and application-free.
ravi-delia 4y ago
With BB it's not so surprising that it's weird because if it weren't, you could cheat! Say you know that a Turing machine which computers digits of the goldbach conjecture has n states. Then if you could just get BB(n), or even if BB(n) is too predictable, you could just run that Turing machine for over BB(n) steps and know it doesn't halt. So we can informally see that BB will necessarily be at least as hard as all of math. Nature abhors a vacuum, but math abhors a shortcut. Every time we find one, it turns out to be deeper and more beautiful than expected.
- Hercuros 4y ago
  To be fair, even if you were able to get BB(n), it might still be (and probably is) some ridiculously large number, like a billion times the number of atoms in the universe or something. So that wouldn't really help you solve any math problems even if you were able to get the maximum amount of steps For a lot of things, like solving boolean SAT, we have the equivalent of a "busy-beaver" limit: if you want to solve a SAT instance of size n, you need at most 2^n steps. And being able to solve arbitrary SAT instances in reasonable time would be huge for mathematical proofs as well, because you could do stuff like find proofs up to a fixed size quickly. Point is that math is probably even harder than BB in some sense, since having BB would not really help you solve math problems in practice most likely.
  - ravi-delia 4y ago
    Oh absolutely, you could never actually use BB(n) even with an oracle on hand. I simplify to cheating on math mostly because it's sort of crazy to think about coming at a problem from that angle (if the Goldbach conjecture is false there's obviously some N where it stops holding, but it's bizarre that you can formulate an N which is independent of the question), but really BB is hard because it's such a slight relaxation of the halting problem. It is a little more interesting (to me at least) than SAT because you expect SAT to be as hard as math. I mean, it's basically just a proof done the long hard way. But even though BB(n) doesn't provide an especially useful upper bound, it does let you expand the halting problem out large enough to use as a bludgeon, since even having information about BB(n) would still let you cheat. It's fun that way!
- dash2 4y ago
  Stupid question: does this imply that busy beaver machines might eventually tell us things about the rest of maths (like are there any real functions that you could say "ah the relevant machine runs for at least BB(n) steps and so we have proved X for infinity"?)
  - cwillu 4y ago
    Kinda, yes, although the implication is typically taken the opposite direction. There are busy beavers who's halting cannot be proven in ZFC! https://scottaaronson.blog/?p=2725 https://scottaaronson.blog/?p=2725