4 ms·
P = V^2 * f, yes, but V and f are correlated. You can't increase f without also increasing V, hence: exponential scaling.
by kec 4y ago
P = V^2 * f, yes, but V and f are correlated. You can't increase f without also increasing V, hence: exponential scaling.
- wormslayer666 4y agoThat's polynomial scaling, not exponential.
- WithinReason 4y agoThat's still a polynomial, not an exponential