3 ms·
> This makes a huge difference because power consumption increases exponentially with clock speed. It scales linearly with clock speed.
by megous 4y ago
> This makes a huge difference because power consumption increases exponentially with clock speed.
It scales linearly with clock speed.
- kec 4y agoP = V^2 * f, yes, but V and f are correlated. You can't increase f without also increasing V, hence: exponential scaling.
- wormslayer666 4y agoThat's polynomial scaling, not exponential.
- WithinReason 4y agoThat's still a polynomial, not an exponential
- msbarnett 4y agoThese graphs look linear to you? https://blog.stuffedcow.net/2012/07/ivy-bridge-power-consumption/ https://blog.stuffedcow.net/2012/07/ivy-bridge-power-consump... https://qph.cf2.quoracdn.net/main-qimg-61820a6b86759c354d41dbbd16a0385b https://qph.cf2.quoracdn.net/main-qimg-61820a6b86759c354d41d...
- megous 4y agoThese graphs look like they depict f only scaling?
- msbarnett 4y agoWho said anything about f? I said "power consumption increases exponentially with clock speed" not "power consumption increases exponentially with f". That any modern processor has to crank up V to crank up its clock speed is a given. Hence, power consumption is exponential with clock speed (which is achieved by cranking up both V - the polynomial term in P – and f). (Which, fine, if you want to be pedantic, is polynomial growth, but that changes nothing about the point, which is that you have to burn a shitload more power at 5 GHz than at 3.2 GHz, because your consumption isn't scaling anything close to linear).
- megous 4y agoClock speed is just f.