i don't understand why o would escape if it's not inlined public int conditionalEscape(boolean cond1) { otherMethod(cond1); MyPair o = ne

i don't understand why o would escape if it's not inlined public int conditionalEscape(boolean cond1) { otherMethod(cond1); MyPair o = new MyPair(/*p1=*/1, /*p2=*/2); return o.getP1(); } the reference still never leaves conditionalEscape (i.e. it's not assigned to a variable outside the methods scope), there's just a layer of indirection.