3 ms·
in a sense, there are only two boys, an inside boy and an outside boy, and where those two boys are together (at around 8 o'clock) you actually don't see 100% o
by fsckboy 5y ago
in a sense, there are only two boys, an inside boy and an outside boy, and where those two boys are together (at around 8 o'clock) you actually don't see 100% of either of them, yet you count it as two boys
in the A position, look at around 8 oclock where the two boys next to each other.
look at the "inside" boy, and then move clockwise and you just see just his foot on the inside, continue and you see a leg, going all the way around you can see almost all of the "inside boy" emerge.
in a like manner, look at the outside boy of the two boys together, and proceeding counter-clockwise you see the foot, the leg, etc as almost all of the outside boy emerges.
it reminds me of a trick where you take a stack of dollar bills and slice a thin strip from each one, with the slice taken on each successive bill moving across, and tape each bill together again.
At the end, tape all the little strips together and you have an extra bill!
- unyttigfjelltol 5y agoYeah, I don't understand why moving the two boys side-by-side is considered a trick. It's much harder to understand how to be misled than to discover the solution.