3 ms·

I wonder how effective grid isolation/'anti islanding protection' is, when the 'island' is big enough, and contains multiple grid tied solar installations. It

I wonder how effective grid isolation/'anti islanding protection' is, when the 'island' is big enough, and contains multiple grid tied solar installations. It probably comes down to how they detect a grid outage. But I can think of some scenarios where the solar inverters can see each other on the grid, and assume the grid is still up

liketochill 5y ago
I think they usually look at the frequency and magnitude of the voltage, if it is outside of say 57.5 to 62 Hz or 80-120% of nominal voltage the inverter probably decides it is no longer connected to the grid. It is possible, but extremely unlikely, that a distributed generation island gets lucky that there is enough generation to meet the load on the island and it can respond fast enough to keep frequency and voltage within range when the island forms.
- franga2000 5y ago
  Dumb question, but how do you measure the voltage on a conductor if you're also putting out that same voltage on that same conductor? For the frequency I can imagine you could probably detect a frequency shift with an independent oscillator, but even then, since the inverter's sine wave is generated electronically, I can't imagine it would follow the usual laws that rotary generators do (frequency changes when supply and load are mismatched). (I'm a software engineer with no formal EE education, so "it's complicated, go read a book first" is also an acceptable answer)
  - deleted 5y ago
    [deleted]
  - liketochill 5y ago
    It is a good question and I don’t design inverters so I don’t really know. I imagine an inverter with one solar panel behind it can’t muster enough oomph to back feed a sizable chunk of distribution network - if it tried it would not be able to maintain nominal voltage. Say the load of the neighborhood is 500 kW, that’s 1200 A at 240V, which the inverter can’t supply unless there is 500 Kw of solar panels behind it. The 500kw load at 240V looks like a 0.2 ohm resistor to the inverter - essentially a short. Actually looking at the impedance of the network is one technique protection relays use to detect line faults. Maybe the inverter can’t sustain the nominal voltage when feeding essentially a short so the voltage will be less then nominal and then it knows it is operating outside or normal conditions. I can’t imagine a scenario in which the inverter could maintain nominal voltage at its terminals with a 0.2 ohm load looking out, if there is 240V across 0.2 ohm then there is 1200A through the 0.2 ohm. In summary despite putting out voltage it will not be able to maintain the desired terminal voltage. For frequency I understand most grid tie inverters somehow follow the grid frequency as opposed to generating their own.

liketochill 5y ago

I think they usually look at the frequency and magnitude of the voltage, if it is outside of say 57.5 to 62 Hz or 80-120% of nominal voltage the inverter probably decides it is no longer connected to the grid. It is possible, but extremely unlikely, that a distributed generation island gets lucky that there is enough generation to meet the load on the island and it can respond fast enough to keep frequency and voltage within range when the island forms.

franga2000 5y ago
Dumb question, but how do you measure the voltage on a conductor if you're also putting out that same voltage on that same conductor? For the frequency I can imagine you could probably detect a frequency shift with an independent oscillator, but even then, since the inverter's sine wave is generated electronically, I can't imagine it would follow the usual laws that rotary generators do (frequency changes when supply and load are mismatched). (I'm a software engineer with no formal EE education, so "it's complicated, go read a book first" is also an acceptable answer)
- deleted 5y ago
  [deleted]
- liketochill 5y ago
  It is a good question and I don’t design inverters so I don’t really know. I imagine an inverter with one solar panel behind it can’t muster enough oomph to back feed a sizable chunk of distribution network - if it tried it would not be able to maintain nominal voltage. Say the load of the neighborhood is 500 kW, that’s 1200 A at 240V, which the inverter can’t supply unless there is 500 Kw of solar panels behind it. The 500kw load at 240V looks like a 0.2 ohm resistor to the inverter - essentially a short. Actually looking at the impedance of the network is one technique protection relays use to detect line faults. Maybe the inverter can’t sustain the nominal voltage when feeding essentially a short so the voltage will be less then nominal and then it knows it is operating outside or normal conditions. I can’t imagine a scenario in which the inverter could maintain nominal voltage at its terminals with a 0.2 ohm load looking out, if there is 240V across 0.2 ohm then there is 1200A through the 0.2 ohm. In summary despite putting out voltage it will not be able to maintain the desired terminal voltage. For frequency I understand most grid tie inverters somehow follow the grid frequency as opposed to generating their own.