3 ms·

Standard deviation of what group?

• chii 5y ago
  of the same/similar job(s) that has been offered by this company (including the past).
  • dllthomas 5y ago
    For large N, that could make some sense. For a lot of (company, job) pairs, though, that'll be an N of 1. That seems unrealistic. Of course we can determine some threshold below which it doesn't apply, but then there are games to be played around how jobs are grouped, etc. I'm not saying there's no solution down that path, but I don't think it's "easy".