3 ms·
If I'm reading that graph correctly, over Oakland there's currently an inversion boundary at ~50m, ~1500m, ~2000m and 14000m. Is a correct interpretation that t
by helaoban 6y ago
If I'm reading that graph correctly, over Oakland there's currently an inversion boundary at ~50m, ~1500m, ~2000m and 14000m. Is a correct interpretation that the smoke is trapped between one or several of these inversion layers, preventing both sinking and upward dispersion?
- labster 6y agoTalking about the 12Z 19 Sep sounding (you might have click back to a previous one if you read this later): The data is a little noisy because it really is just a weather balloon getting knocked around. There's a huge inversion from 300-500m. Then the temperature is roughly constant between 1500-2500m (the T line is skewed), and we finally get a big decrease in temperature below that. The 14000m one is normal, this is called the tropopause. Normally it's a bit lower than that, but heck, even the 500mb level is at 588dm heights. It's hot out there. So really, nothing is going to sink below that 500m point. Now, lots of Mount Diablo is above 300m -- it's going to be hot and smokey up there. But if you tried to push a parcel of air down from 500m, it would be so much less dense than the cool moist air below that it would bounce back up. The whole troposphere is very stable, but extremely so at that level. Most people who look at skew-Ts are interested in thunderstorms -- the area of the blue line to the right of the red line tells you how much energy you can release from condensation of water, with some air from the surface rising. Like, look at Brownsville, Texas: https://climate.cod.edu/products/analysis/raob/index.php?type=conus-current-current-skewt-KBRO-0 https://climate.cod.edu/products/analysis/raob/index.php?typ...