4 ms·
This makes 0 sense. Firstly, if you're rounding to the nearest 5c, you can round up both $x.x3 and $x.x8, and get fair rounding. Perhaps you are thinking of the
by dmurray 7y ago
This makes 0 sense. Firstly, if you're rounding to the nearest 5c, you can round up both $x.x3 and $x.x8, and get fair rounding. Perhaps you are thinking of the slightly more complicated deal with rounding to the nearest 10c, where you round down $x.05 and up $x.15.
And Benford's law applies to leading digits, not the least significant digit. It's right there in the first line of your link.
- Scoundreller 7y agoYou are correct about the unusual rounding to the nearest 10 cents. But Benford's law extends to less significant digits, just decreasingly so. See https://en.wikipedia.org/wiki/Benford%27s_law#Generalization_to_digits_beyond_the_first https://en.wikipedia.org/wiki/Benford%27s_law#Generalization... That's why the link says "leading digits", not "most significant digit".